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HELP PLS I WILL GIVE BRAINLIEST !

The dimensions of these rectangles are given to the level of accuracy indicated in brackets.
(I) 8cm x 12cm (nearest cm)

Ans :

(II) 8.3cm x 12.5cm(1 decimal place)
Ans :

(II) (2 significant figures)

Ans :


Calculate for each:
(a) The upper and lower bounds for the Perimeter.

Respuesta :

unicornetfairies

Answer:

I) 8x12=96cm^2

Probably 96.0 to 2 s.f

II)8.3x12.5=103.75cm^2

so it's 103.8cm^2 to 1 d.p and 100 to 2 s.f

Perimeter

I) 8cm

Lower bound is 7.5

Higher bound is 8.5

12cm

Lower bound is 11.5 and upper bound is 12.5

Ans:

Lower first -

(7.5 x 2) + (11.5 x 2) = 38cm

To 2 s.f is 38.0cm

Higher next -

2 x (8.5+12.5)= 42cm

To 2 s.f is 42.0cm

Perimeter

II)8.3cm x 12.5cm(1 decimal place)

1d.p is 0.1

0.1/2 =0.05

8.3

Lowest is 8.25cm (8.30 - 0.05)

Highest is 8.35cm (8.30 + 0.05)

12.5

Lowest is 12.45cm (12.50 - 0.05)

Highest is 12.55cm (12.50 + 0.05)

Ans:

Lower first -

2 x (8.25+12.45) = 41.4cm

To 2 s.f is 41.0cm

Higher next -

2 x (8.35+12.55) = 41.8cm

To 2 s.f is 42.0cm

Hope this helps!

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