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What is the acceleration of an object that is initially moving at 10.5 m/s and is moving at 13.5 m/s after 2 seconds

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Answer:Hope it will help you.

Explanation:

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Answer:

[tex]\boxed {\boxed {\sf a= 1.5 \ m/s^2}}[/tex]

Explanation:

Acceleration is the change in velocity over time, so it is calculated using the following formula.

[tex]a= \frac{v_f-v_i}{t}[/tex]

The object is initially moving at 10.5 meters per second. After 2 seconds, it is moving at 13.5 meters per second.

  • [tex]v_i[/tex]= 10.5 m/s
  • [tex]v_f[/tex]=13.5 m/s
  • t= 2 s

Substitute the values into the formula.

[tex]a= \frac{13.5 \ m/s - 10.5 \ m/s}{2 \ s}[/tex]

Solve the numerator.

[tex]a= \frac{3 \ m/s}{2 \ s}[/tex]

Divide.

[tex]a=1.5 \ m/s/s \\a= 1.5 \ m/s^2[/tex]

The acceleration of the object is 1.5 meters per second squared.