If the field strength is e = 9 v/m a distance of 1 m from the charge, what is the field strength e a distance of 3 m from the charge?

The field strength is directly proportional to the square of the distance. Therefore, we can use the relation:
e1 d1² = e2 d2²
where
e1 = 9 v/m
d1 = 1 m
d2 = 3 m
Substituting
9 (1)² = e2 (3²)
e2 = 1 v/m

Answer Link

pinquancaro pinquancaro · Answer 2 · 2019-11-28T05:40:19+01:00

Answer:

The field strength is 1 V/m.

Step-by-step explanation:

Given : If the field strength is E = 9 V/m a distance of 1 m from the charge.

To find : What is the field strength E a distance of 3 m from the charge?

Solution :

The formula of Electric field strength is

[tex]E=\frac{kq}{r^2}[/tex]

where, E=9 V/m is electric field strength

q is the charge

r=1 m is the distance

Substitute the value in the formula,

[tex]9=\frac{kq}{1^2}[/tex]

[tex]9 Vm=kq[/tex]

Now, to find field strength a distance of 3 m from the charge

i.e. kq=9 Vm and r=3

Substitute the value in the formula,

[tex]E=\frac{9}{3^2}[/tex]

[tex]E=\frac{9}{9}[/tex]

[tex]E=1\ V/m[/tex]

The field strength is 1 V/m.