Akopa
contestada

Determine (a) the peak frequency deviation, (b) minimum bandwidth,and (c) baud for a binary FSK signal with a mark frequency of 38 kHz, a space frequency of 40 kHz, and an input bit rate of 4 kbps​

Respuesta :

The peak frequency deviation, minimum bandwidth, and baud for a binary FSK signal for the given frequencies are respectively;

a) 0.5 kHz

b) 9 kHz

c) 4000

Peak frequency deviation

1) The peak frequency deviation is gotten from the formula;

∆f = |f_m - f_s|/f_b

where;

  • f_m is mark frequency
  • f_s is space frequency
  • f_b is input bit rate

Thus;

∆f = |38 - 40|/4

∆f = 0.5 kHz

2) The minimum bandwidth is given by the formula;

B = 2(∆f + f_b)

B = 2(0.5 + 4)

B = 9 kHz

3) For FSK signal, N = 1, and the baud is gotten from the Equation;

baud = f_b/1

f_b = 4 kbps = 4000 bps

Thus; baud = 4000/1 = 4000

Read more about peak frequency at; https://brainly.com/question/26044136

Otras preguntas