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A soccer ball of mass 0.50 kg is rolling with velocity <0,0,1.8>m/s when you kick it. Your kick delivers an impulse of magnitude 1.5 N · s in the −x direction. The net force on the rolling ball, due to the air and the grass, is 0.29 N in the direction opposite to the direction of the ball's momentum. Using a time step of 0.5 s, find the position of the ball at a time 1.5 s after you kick it, assuming that the ball is at the origin at the moment it is kicked. Use the approximation

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MissPhiladelphia
We are given with the impulse which will allow us to determine the velocity of the ball after the kick
1.5 = 0.5 (v - 1.8)
v = 4.8 m/s
We can determine the acceleration using newton's second law of motion
0.29 = 0.5 a
a = 0.58 m/s2
Using the formula for kinematics
y = v0t + 0.5at^2
y = 4.8 (1.5) + 0.5 (0.58)(1.5)^2
y = 7.85 m to the left of the origin

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