sutyprown
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An automobile purchased for $34,800 is worth $8550 after 7 years. Assuming that the car's value depreciated steadily from year to year, what was it worth at the end of the third year?

Respuesta :

col08
I've calculated how much the car depreciated every year which is about $3,757
In three years, that is 11,271. 
$34,800 - $11,271= $23,528
The automobile cost $23,528 at the end of the third year.

Answer:

The car's worth at the end of the third year is $23550.

Step-by-step explanation:

An automobile purchased for $34,800 is worth $8550 after 7 years.

So, annual depreciation was = [tex]\frac{34800-8550}{7}[/tex]

= [tex]\frac{26250}{7}[/tex] = $3750

So, in 3 years this depreciation value would have been = [tex]3750\times3=11250[/tex] dollars

Hence, the value of the car at the end of the third year = [tex]34800-11250=23550[/tex] dollars

The car's worth at the end of the third year is $23550.

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