Using simple interest, it is found that the maturity value of the loan is of 10,638.
The amount of money after t years in simple interest is modeled by:
[tex]A(t) = A(0)(1 + rt)[/tex]
In which:
In this problem:
Then, the maturity value of the loan is:
[tex]A(t) = A(0)(1 + rt)[/tex]
[tex]A\left(\frac{75}{365}\right) = 10450\left[1 + 0.0875\frac{75}{365}\right] = 10638[/tex]
The maturity value of the loan is of 10,638.
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