A normal distribution of data has a mean of 90 and a standard deviation of 18. What is the approximate z-score for the value 64? –3. 6 –1. 4 1. 4 3. 6.

Respuesta :

The value of the z-score is -1.4.

Given that

A normal distribution of data has a mean of 90 and a standard deviation of 18.

We have to determine

What is the approximate z-score for the value 64?

According to the question

The z-score is determined by the following formula given below;

[tex]\rm Z-score = \dfrac{x-Mean}{Standard \ deviation}[/tex]

A normal distribution of data has a mean of 90 and a standard deviation of 18.

And the value of x is 64.

Therefore,

The value of the z-score is,

[tex]\rm Z-score = \dfrac{x-Mean}{Standard \ deviation}\\\\\rm Z-score = \dfrac{64-90}{18}\\\\\rm Z-score = \dfrac{-26}{18}\\\\\rm Z-score = -1.4[/tex]

Hence, the value of the z-score is -1.4.

To know more about Z-score click the link given below.

https://brainly.com/question/795909