A spring that has a spring constant of 440 N/m exerts a force of 88 N on a box. What is the displacement of the spring? 0. 2 m 5 m 352 m 528 m.

Respuesta :

The displacement of a spring is directly proportional to the applied force. The displacement of the given spring is 50.45 m.

From Hooke's law:

[tex]F = kx[/tex]

Where,

[tex]F[/tex] - force applied = 88 N

[tex]k[/tex] - spring constant = 440 N/m

[tex]x[/tex] - displacement = ?

Put the values in the formula,

[tex]88 = 440 \times x\\\\x = \dfrac {440 }{88}\\\\x = 50.45 \rm \ m[/tex]

Therefore, the displacement of the given spring is 50.45 m.

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