Answer:
The slope of a line that passes through (-2, -3) and (1, 1) is 4/3.
Step-by-step explanation:
Here's the required formula to find slope line :
[tex]\star{\underline{\boxed{\sf{m = \dfrac{y_2 - y_1}{x_2 - x_1}}}}}[/tex]
Here, we have provided :
[tex]\begin{gathered} \footnotesize\rm {\underline{\underline{Where}}}\begin{cases}& \sf y_2 = 1\\& \sf y_1 = - 3\\ & \sf x_2 = 1\\ & \sf x_1 = - 2\end{cases} \end{gathered}[/tex]
Substituting the values in the formula to find slope line :
[tex] \begin{gathered} \qquad{\longrightarrow{\sf{m = \dfrac{y_2 - y_1}{x_2 - x_1}}}} \\ \\ \qquad{\longrightarrow{\sf{m = \dfrac{(1) - ( - 3)}{1 - ( - 2)}}}} \\ \\ \qquad{\longrightarrow{\sf{m = \dfrac{1 + 3}{1 + 2}}}} \\ \\ \qquad{\longrightarrow{\sf{m = \dfrac{4}{3}}}} \\ \\ \qquad{\star{\underline{\boxed{\frak{m = \dfrac{4}{3}}}}}} \end{gathered}[/tex]
Hence, the slope line is 4/3.
[tex]\rule{300}{2.5}[/tex]
