Answer:
[tex]\frac{1}{3}[/tex]
Step-by-step explanation:
Total number of events on dice = {1,2,3,4,5,6}=6
Favorable event = {3}=1
So, probability of getting 3 on dice = [tex]\frac{\text{Favorable events }}{\text{Total events}}[/tex]
= [tex]\frac{1}{6}[/tex]
Favorable event = {4}=1
So, probability of getting 4 on dice = [tex]\frac{\text{Favorable events }}{\text{Total events}}[/tex]
= [tex]\frac{1}{6}[/tex]
So, probability of getting 3 or 4 on a dice = [tex]\frac{1}{6}+\frac{1}{6}[/tex]
= [tex]\frac{2}{6}[/tex]
= [tex]\frac{1}{3}[/tex]
Hence P(3 or 4) is [tex]\frac{1}{3}[/tex]
