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A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account?

Which of the following equations could be used to solve the problem?

A.)0.02x + 0.04(800) = 112
B.)0.02x + 0.04(x + 800) = 112
C.)0.04x + 0.02(x + 800) = 112

Respuesta :

.02x+.04*2x=112
.02x+.08x=112
.10x=112
x=112/.10
x=$1,120 invested @ 2%.
2*1,120=$2,240 amount invested @ 4%.
Proof:
.02*1,120+.04*2,240=112
22.4+89.6=112
112=112
anniego4

A.) 0.02x + 0.04(800) = 112

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