What is the equation of the line in slope-intercept form?

Answer:
y = 8x + 0 or y = 8x
Step-by-step explanation:
Given the graph of a positive-sloped line passing through the point of origin:
In order to determine the linear equation in slope-intercept form, y = mx + b, we must solve for the slope of the line.
Let's use the following points on the graph:
(x₁, y₁) = (0, 0)
(x₂, y₂) = (2, 16)
Substitute these values into the following slope formula:
m = (y₂ - y₁)/(x₂ - x₁)
m = (16 - 0)/(2 - 0)
m = 16/2
m = 8
Thus, the slope of the line is m = 8.
Next, we must determine the y-intercept, which is the point on the graph where it crosses the y-axis.
The line crosses at the point of origin, (0, 0), which means that the y-intercept, b = 0.
Therefore, the linear equation in slope-intercept form is: y = 8x + 0 or y = 8x.
Answer:
[tex]\displaystyle y = 8x[/tex]
Step-by-step explanation:
Start from the y-intercept of [tex]\displaystyle [0, 0][/tex]and move eight units south over one unit west. They both are negative integers, so when divided, you get a positive integer:
[tex]\displaystyle 8 = \frac{-8}{-1}[/tex]
Moreover, this function is what is considered direct variation because the graph intersects the origin.
Well, there you have it. I am joyous to assist you at any time.