pls help me answer and understand this

1.
The value of y in the diagram where ACD and BCD are straight lines is 109°
∠CED = 95°
2. ∠CBD is 134°
The value of b in the figure where ABC, ADF and BDE are straight line is 54°
1.
ACD and BCD are straight lines.
∠ACB = 180 - 34 - 75 = 71° (sum of angle in a triangle)
Therefore,
y = 180 - ∠ACB (angle on a straight line)
y = 180 - 71 = 109°
∠DCE = 71° (vertically opposite angles)
∠CED = 180 - 71 - 14 = 95° (sum of angles in a triangle)
2.
ABC, ADF and BDE are straight line.
The sum of the opposite interior angle is equals to the exterior angle.
Therefore,
∠CBD = 93 + 41
∠CBD = 134°
∠EDF = 93°(vertically opposite angles)
b = 180 - 33 - 93 = 54° (sum of angles in a triangle)
learn more on angles here: https://brainly.com/question/17984900