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What is the period of a satellite in a circular orbit just above the surface of the Moon? The Moon’s mass is 7.36 × 1022 kilograms and its radius is 1.738 × 106 meters.

Respuesta :

Answer:

F / m = a = G M / R^2            formula for gravitational attraction

a = ω^2 R   formula for centripetal force for an object with radius R

G M / R^2 = ω^2 R equating accelerations

ω = (G M / R^3)^1/2

ω = 2 pi f = 2 pi / P      for circular motion

P = 2 pi (R^3 / (G M))^1/2

R^3 / (G M) = (1.738E6)^3 / (6.67E-11 * 7.36E22)  = 1.07E6

P = 6.28 * 1034 sec = 6500 sec = 1.80 hrs

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