Respuesta :

The value of d²y/dx² at (3, 8) is -25/32.

Since 4x² + y² = 100, we differentiate implicitly twice with respect to x to get d²y/dx².

So, d(4x² + y²)/dx = d100/dx

d(4x²)/dx + d(y²)/dx = 0

8x + 2ydy/dx = 0

2ydy/dx = -8x

dy/dx = -8x/2y

dy/dx = -4x/y

Differentiating again with respect to x, to have d²y/dx² the second derivative . So, we have

d(dy/dx)/dx = d(-4x/y)/dx

Using the quotient rule

d(u/v)/dx = [vdu/dx - udv/dx]/v²

With u = -4x and v = y

d²y/dx² = [yd(-4x)/dx - (-4x)dy/dx]/y²

d²y/dx² = [-4y + 4xdy/dx]/y²

Substituting dy/dx into the equation, we have

d²y/dx² = [-4y + 4xdy/dx]/y²

d²y/dx² = [-4y + 4x(-4x/y)]/y²

d²y/dx² = [-4y - 16x²/y)]/y²

d²y/dx² = [-4y² - 16x²]/y³

d²y/dx² = -4[y² + 4x²]/y³

Since we require the value of d²y/dx² at (3, 8), x = 3 and y = 8.

So, substituting these values into the equation, we have

d²y/dx² = -4[y² + 4x²]/y³

d²y/dx² = -4[8² + 4(3)²]/8³

d²y/dx² = -4[64 + 4(9)]/512

d²y/dx² = -4[64 + 36]/512

d²y/dx² = -4[100]/512

d²y/dx² = -100/128

d²y/dx² = -25/32

So, the value of d²y/dx² at (3, 8) is -25/32.

Learn more about second derivative here:

https://brainly.com/question/25508224