Answer: A. Velocity
Explanation:
The fluid flow through a pipe has the constant flow rate, so:
Q1 = Q2
Then, A1 V1 = A2 V2
That means, if A1 increases, V1 will decrease in order to keep the flow rate constant. Mass stays the same since it has the same system, which is pipe. Flow rate stays the same, and density also stays the same since it consists of one type of fluid (i.e. water).
Velocity will decrease. The correct option is A.
The equation for flow [tex]Q[/tex],
[tex]Q = A\times V\\\rm where,\\A = cross\ sectional\ area\\V = Velocity\ of\ the\ fluid[/tex]
As the per the equation of continuity. for the same fluid in a pipe (properties of fluid are constant) the flow at the inlet[tex](Q_1)[/tex] and outlet[tex](Q_2)[/tex] of the pipe will be constant. Therefore,
[tex]Q_1 = Q_2\\Q_1 =A_1 \times v_1\\Q_2 =A_2 \times v_2\\hence,\\A_1 \times v_1 = A_2 \times v_2[/tex]
Hence, if the area is increased therefore to keep the flow constant, velocity will decrease.
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