Answer:
xy1
Step-by-step explanation:
Correct option is C)
Given two equations are 2x+y+4=0 and x=3y+7=0
let us consider 2 equations ax+by+c=0 and mx+ny+p=0
By cross multiplication method ,the equations obtained will be ,
b×p−n×c
x
=
c×m−a×p
y
=
a×n−b×m
1
Thus comparing it with given 2 equations we obtain:
7−12
x
=
4−14
y
=
6−1
1
