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The perpendicular bisector of a line segment is a line perpendicular to the segment that passes through its midpoint. What is the equation for the perpendicular bisector of segment XY with point X(2, -6) and Y(5, -5)?

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ilyons40

Answer:

y = 1/3 x.

Step-by-step explanation:

The slope of the given line is

(4 - (-2) / 2 - 4)

=   -3.

So the slope of the line perpendicular to it = -1 / (-3) = 1/3.

This line also passes through the point (3, 1) so its equation is ( by the point-slope form):

y - 1 = 1/3(x - 3)

y - 1 = 1/3x - 1

y = 1/3 x (answer).

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