[tex]\text{Given that,}\\\\(x_1,y_1) = (3,8)~~ \text{and}~~ (x_2,y_2) = (5,14)\\\\\\\text{Slope, m}= \dfrac{y_2 -y_1}{x_2 -x_1} = \dfrac{14-8}{5-3} = \dfrac 62 =3\\\\\\\text{Equation with given points,}\\\\y-y_1 = m(x-x_1)\\\\\implies y-8 = 3(x-3)\\\\\implies y -8=3x-9\\\\\implies y = 3x -9 +8\\\\\implies y = 3x -1[/tex]