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According to Lavoisier's law, in the given reaction the mass of zinc produced will be 104 g.
Let's consider the following reaction.
Ca + ZnCO₃ ⇒ CaCO₃ + Zn
64g 192 g 152 g ? g
Lavoisier's law states that the sum of the masses of the reactants before the reaction is equal to the sum of the masses of the products after the reaction.
mCa + mZnCO₃ = mCaCO₃ + mZn
mZn = mCa + mZnCO₃ - mCaCO₃
mZn = 64 g + 192 g - 152 g = 104 g
What would be the amount of zinc formed during the reaction?
According to Lavoisier's law, in the given reaction the mass of zinc produced will be 104 g.
Learn more about Lavoisier's law here: https://brainly.com/question/11429078