Given that Angelo spends the same amount everyday from the amount in
the lunch card, the function of the amount remaining is a linear function.
- The constant rate of change of the function is; -5.25
- The two ordered pair used to find the constant rate of change are; (1, 44.75) and (2, 39.5)
Reasons:
The amount Angelo's mother put on the lunch card = $50
A possible table of values to the question is presented as follows;
[tex]\begin{tabular}{r|c|c|c|c|}Days&0&1&2&3\\Money Remaining&&44.75&39.5&\end{array}\right][/tex]
Required:
The constant rate of the function that gives the amount remaining from the
amount Angelo's mother put on his lunch card.
Solution:
- [tex]Slope \ or \ constant \ rate \ of \ change = \mathbf{\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}[/tex]
The two ordered pair that can be used to find the slope or constant rate of change are;
(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)
With the above two ordered pairs, we have the constant rate of change of the function given as follows;
[tex]Constant \ rate \ of \ change\ (The \ slope) =\dfrac{39.5-44.75}{2-1} = \mathbf{ -5.25}[/tex]
The constant rate of change for the function that gives the amount remaining in the lunch card is; -5.25
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