8. Assuming str(rate) is "7.25," what output would be produced by the following snippet:
print("The hourly parking rate is $." + str(rate))


O "The hourly parking rate is $7.25"

O "The hourly parking rate is $ 7.25"

O "The hourly parking rate is $." "7.25"

O The print comfwand would fail because the rate is an integer, not a string,

Respuesta :

The output would be "The hourly parking rate is $7.25"

The question is an example of concatenation.

Concatenation is an operation in computer programming in which a string is added to another string with the binary operation, '+' or '*'.

So, 'Frank' + 'Peter' concatenates as 'FrankPeter' and 'a' *3 concatenates as 'aaa'.

Since str(rate) is "7.25," which is a string, and the snippet is print("The hourly parking rate is $." + str(rate)), str(rate) will concatenate and be added to the expression "The hourly parking rate is $."

So, the output would be "The hourly parking rate is $7.25"

Note that since there is no space at the end of the first string, the second string is added to the first string directly without any spacing between the '

sign and the '7'.

So, the output would be "The hourly parking rate is $7.25"

Learn more about concatenation here:

https://brainly.com/question/17031234