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A 100 g mass of tungsten at 100.0°C is placed in 200 g of water at 20.0°C. The
mixture reaches equilibrium at 21.6°C. Calculate the specific heat of tungsten

Respuesta :

ok so basically

If you,
q= 100g x 4.186 j/g*degrees C * (21.6 degrees C- 20.0 degrees C) which equals to 1.6.

So q= 100g * 4.186 j/g*deg C * 1.6
Eduard22sly

The specific heat capacity of tungsten given the data from the question is 0.17 J/gºC

Data obtained from the question

Mass of tungsten (M) = 100 g

Temperature of tungsten (T) = 100 °C

Mass of water (Mᵥᵥ) = 200 g

Temperature warm water (Tᵥᵥ) = 20 °C

Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC

Equilibrium temperature (Tₑ) = 21.6 °C

Specific heat capacity of tungsten (C) = ?

How to determine the specific heat capacity of tungsten

Heat loss = Heat gain

MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

100 × C × (100 – 21.6) = 200 × 4.184(21.6 – 20)

100 × C × 78.4 = 1338.88

Divide both sides by 100 × 78.4

C = 1338.88 / (100 × 78.4 )

C = 0.17 J/gºC

Learn more about heat transfer:

brainly.com/question/6363778

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