A sporting event held at a high school had 135
attendees. The event earned a total of $930.
Admission to the event was $10 for adults and
$4 for students. How many adults (a) and how
many students (s) attended?
a + s = 135
10a + 4s = $930
[?] adults [ ] students

A sporting event held at a high school had 135 attendees The event earned a total of 930 Admission to the event was 10 for adults and 4 for students How many ad class=

Respuesta :

Answer:

65 adults and 70 students

The number of adults and students attendant the sporting event held at a high school are 65 and 70 respectively .

What is elimination method?

In the elimination method, we eliminate any one of the variables by using basic arithmetic operations and then simplify the equation to find the value of the other variable. Then we can put that value in any of the equations to find the value of the variable eliminated.

According to the question

A sporting event held at a high school had 135 attendees.

In which adults and students are there .

Let adults be a

and students be s

Therefore,

The equation is

a + s = 135 ---------------------------(1)

Now,

The event earned a total of $930.

Admission to the event was $10 for adults and $4 for students.

i,e

10a + 4s = 930 ---------------------------(2)

Now , Using elimination method to solve both equations

a + s = 135 ---------------------------(1)

10a + 4s = $930 -------------------(2)

Step1: Multiplying equation 1 by 10

i,e

10a + 10s = 1350 -------------------(3)

Step2: Subtract equation (2) from (3)

10a + 10s = 1350 -------------------(3)

-10a - 4s = -930 -------------------(2)

6s = 420

s = 70

Now , Substituting the value of s in equation (1)

a + s = 135 ---------------------------(1)

a + 70 = 135

a = 65

Hence, The number of adults and students attendant the sporting event held at a high school are 65 and 70 respectively .

To know more about elimination method here:

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