Using vector concepts, it is found that the components of the velocity are given as follows:
Given a magnitude M and angle [tex]\theta[/tex], the a vector V can be represented as follows:
[tex]V = M\sin{\theta}i + M\cos{\theta}j[/tex]
In which:
In this problem, we have that the magnitude and the angle are given as follows:
[tex]M = 600, \theta = 70^{\circ}[/tex]
Hence the north component is:
[tex]600\cos{70^{\circ}} = 205.21[/tex]
And the east component is:
[tex]600\sin{70^{\circ}} = 563.82[/tex]
More can be learned about vectors at brainly.com/question/24606590
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