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A sample of a gas in a 4L container at 300K has a pressure of 1 atm. If the
temperature is increased to 600K and the volume is decreased to 2L , the
pressure is likely to be closest to which of the following? *
O 0.5 atm
1 atm
4 atm
2 atm

Respuesta :

Eduard22sly

The final pressure of the gas in the container is 4 atm

From the question given above, the following data were obtained:

Initial volume (V₁) = 4 L

Initial temperature (T₁) = 300 K

Initial pressure (P₁) = 1 atm

Final temperature (T₂) = 600 K

Final volume (V₂) = 2 L

Final pressure (P₂) =?

  • Using the combine gas equation, we can obtain the final pressure of the gas as illustrated below:

[tex]\frac{P_{1} V_{1} }{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}\\\\\frac{1 * 4}{300} = \frac{P_{2} * 2}{600} \\\\[/tex]

Cross multiply

300 × 2 × P₂ = 4 × 600

600 × P₂ = 2400

Divide both side by 600

[tex]P_{2} = \frac{2400}{600} \\\\[/tex]

P₂ = 4 atm

Therefore, the final pressure of gas is 4 atm.

Learn more: https://brainly.com/question/23558057

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