Ana is a teacher who plays a review game with her class. The game involves writing each student's name on
an identical slip of paper and selecting students at random. Here's the makeup of her class:
Grade
9th 10th 11th
Number of students
12. 9. 7.
Suppose that Ana picks a name, replaces it, and picks a name again.

What is the probability that NEITHER of the students selected are
9th graders?
Round your answer to two decimal places.

Ana is a teacher who plays a review game with her class The game involves writing each students name on an identical slip of paper and selecting students at ran class=

Respuesta :

Answer:

P(Neither 9th grade)=16/28*16/28=16/28*16/28=(16/28)^2=256/784≈0.3265

Answer:

The probability that neither of the students selected are 9th  graders is about 0.33.

Step-by-step explanation:

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Probabilities are used to determine the chances of events

The probability that neither of the students is a 9th grader is 0.33

From the table, the number of students that are not 9th graders are:

[tex]N9 =9 + 7[/tex]

[tex]N9 =16[/tex]

The total number of students is:

[tex]Total =12 + 9 + 7[/tex]

[tex]Total =28[/tex]

The probability that neither of the students is a 9th grader is calculated as follows

[tex]P =P(N9) \times P(N9)[/tex]

So, we have:

[tex]P =\frac{16}{28} \times \frac{16}{28}[/tex]

Multiply

[tex]P =\frac{256}{784}[/tex]

Divide and approximate

[tex]P =0.33[/tex]

Hence, the probability that neither of the students is a 9th grader is 0.33

Read more about probabilities at:

https://brainly.com/question/7965468