The area of the flag when the base is 2 inches and the height is 2.5 inches is 2.5 square inches
From the question, we understand that the area (A) of the flag varies jointly with the base (B) and the height (H)
This variation is represented as:
[tex]\mathbf{A\ \alpha\ B \times H}[/tex]
So, we have:
[tex]\mathbf{A\ \alpha\ BH}[/tex]
Express as an equation
[tex]\mathbf{A\ =k BH}[/tex]
When the area is 1.5 square inches, the base is 1.5 inches and the height is 2 inches, we have:
[tex]\mathbf{A\ =k BH}[/tex]
This gives
[tex]\mathbf{1.5\ =k \times 1.5 \times 2}[/tex]
[tex]\mathbf{1.5\ =k \times 3}[/tex]
Divide both sides by 3
[tex]\mathbf{\frac 12 =k }[/tex]
Rewrite as:
[tex]\mathbf{k = \frac 12}[/tex]
When the base is 2 inches and the height is 2.5 inches, we have:
[tex]\mathbf{A\ =k BH}[/tex]
This gives
[tex]\mathbf{A = \frac 12 \times 2 \times 2.5}[/tex]
[tex]\mathbf{A = 2.5}[/tex]
Hence, the area of the flag is 2.5 square inches
Read more about variations at:
https://brainly.com/question/14251450
