Respuesta :

Answer:

You can use the exponential rule where

[tex](n^x)^y=n^{xy}[/tex]

Therefore,

[tex](a^3)^{-2}=a^{3*(-2)}=a^{-6}[/tex]

[tex]\\ \rm\leadsto (a^3)^{-2}[/tex]

  • (a^m)^n=a^mn

[tex]\\ \rm\leadsto a^{-6}[/tex]

[tex]\\ \rm\leadsto \dfrac{1}{a^6}[/tex]