A car is moving at a speed of 72 km / h on a horizontal section. What is the braking distance of the car if the friction force is equal to the size of the weight of the car? (20 m) (+ formula)

Respuesta :

Answer:

20.4m

Explanation:

72kmhr(1000mkm)(hr3600sec)=20ms  

Use principles of conservation of energy.

The initial kinetic energy of the car is equal to the work done by friction during braking:

KE=Wfric  

12mv2=(Ffric)d  

but the force of friction = weight of the car = mg

12mv2=mgd  

mass cancels in both terms, which tells us the answer is independent of mass

12v2=gd  

12202=(9.81)d  

d=20.4m  

Note that the correct answer should actually be 20. m with only 2 significant figure accuracy since 72 km/hr only has 2 sig fig accuracy.