9514 1404 393
Answer:
0.40+2.20i
Step-by-step explanation:
To clear the denominator of its imaginary part, multiply numerator and denominator by the conjugate of the denominator.
[tex]\dfrac{3+4i}{2-i}=\dfrac{(3+4i)(2+i)}{(2-i)(2+i)}=\dfrac{6-4+3i+8i}{4+1}=\dfrac{2+11i}{5}\\\\=\boxed{0.40+2.2i}[/tex]
_____
Additional comment
This "multiply by the conjugate" is also used to clear radicals from the denominator. It takes advantage of the factoring of the difference of squares:
(a -b)(a +b) = a² -b²
