A pollutant breaks down at a rate of 2% a year. What fraction of the current amount will be present in 20 years? Let X(0) = 1.

Respuesta :

Answer:

Step-by-step explanation:

X = 1(1 - 0.02)ⁿ

X = 1(0.98)²⁰

X = 0.6676

67%

Using an exponential equation, it is found that 66.76% of the current amount will be present in 20 years.

A decaying exponential function has the following format:

[tex]A(t) = A(0)(1 - r)^t[/tex]

In which:

  • A(t) is the initial value.
  • r is the decay rate, as a decimal.

In this problem, breaks down at a rate of 2% a year, hence [tex]r = 0.02[/tex], and:

[tex]A(t) = A(0)(1 - 0.02)^t[/tex]

[tex]A(t) = A(0)(0.98)^t[/tex]

The fraction after 20 years is A(20), hence:

[tex]A(20) = A(0)(0.98)^{20}[/tex]

[tex]A(20) = 0.6676[/tex]

66.76% of the current amount will be present in 20 years.

A similar problem is given at https://brainly.com/question/14773454