[tex]\large\boxed{\tt\:Question}[/tex]
x² - 8x + 12 = 0
Hello meremyj! Here's your answer with explanation.
[tex]\large\boxed{\tt\:Answer\:with\:Explanation}[/tex]
[tex]x ^ { 2 } - 8 x + 12[/tex]
Use the biquadratic formula =》 [tex]x=\frac{-b±\sqrt{\left(-b\right)^{2}-4 ac}}{2}[/tex]
Now,
Using the biquadratic formula & substituting the values....
[tex]x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\times 12}}{2} \\x=\frac{-\left(-8\right)±\sqrt{64-4\times 12}}{2} \\x=\frac{-\left(-8\right)±\sqrt{64-48}}{2} \\x=\frac{-\left(-8\right)±\sqrt{16}}{2} \\x=\frac{-\left(-8\right)±4}{2} \\\underline{\underline{x=\frac{8±4}{2}} }[/tex]
Now, solve when [tex]x=\frac{8+4}{2}[/tex]
[tex]x=\frac{8+4}{2}\\x=\frac{12}{2} \\\boxed{\bf\:x=6 }[/tex]
Now, solve when [tex]x = \frac{8-4}{2}[/tex]
[tex]x = \frac{8-4}{2}\\x = \frac{4}{2}\\\boxed{\bf\:x=2}[/tex]
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- The value of x can be 6 & 2.
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Hope it'll help you!
Lucäžž
