contestada

Challenge The price of Stock A at 9 A.M. was $14.63. Since then, the price has been increasing at the
rate of $0.09 each hour. At noon the price of Stock B was $15.13. It begins to decrease at the rate of
$0.11 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the
same?
In about
hours, the prices of the two stocks will be the same.

Respuesta :

sqdancefan

9514 1404 393

Answer:

  2.5 hours

Step-by-step explanation:

The price of stock A is described by ...

  A = 14.63 + 0.09t . . . . . . where t is time in hours after 9 A.M.

And the price of stock B is ...

  B = 15.13 - 0.11t

The two prices will be equal when ...

  A = B

  14.63 +0.09t = 15.13 -0.11t

  0.20t = 0.50 . . . . . . . . . . . . . add 0.11t -14.63 to both sides

  t = 0.50/0.20 = 2.5

The prices of the two stocks will be the same in about 2.5 hours.

Otras preguntas