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A car traveling north with a velocity of 33 m/sec slows down to a velocity of 12 m/sec north within 10 sec. What is the car’s deceleration?

Respuesta :

kz0243546

a=v/t

v= 33-12 = 21

21÷10=2.1

a= 2.1
33 m/s north is initial velocity (Vi). 12 m/s north is final velocity (Vf). 10s is the time. The equation for acceleration is Vf-Vi/t. 12-33 is -21. -21 divided by 10 is -2.1. The answer is -2.1 m/s^2 North.

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