Answer:
[tex]y = \frac{1}{-1}x + 0[/tex] [tex]or[/tex] [tex]y = \frac{1}{-1}x[/tex]
Step-by-step explanation:
[tex]y = mx + c[/tex]
[tex]m = \frac{y_{2} -y_{1}}{x_{2} - x_{1} } }[/tex]
[tex](x_{1},y_{1}) = (-1,1)\\(x_{2},y_{2}) = (-2,2)[/tex]
[tex]m = \frac{2 - 1}{(-2) - (-1)}[/tex]
[tex]m = \frac{2 - 1}{-2 +1 }[/tex]
[tex]m = \frac{1}{-1}[/tex]
[tex]c = 0[/tex]
[tex]y = \frac{1}{-1}x + 0[/tex] [tex]or[/tex] [tex]y = \frac{1}{-1}x[/tex]
