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A box contains 8 red, 6 yellow, and 7 blue marbles. A marble is drawn, not replaced, and a second marble is
drawn. What is the probability of selecting 2 yellow marbles?

Respuesta :

jaydenprince115

Answer:

Probability=

(number if outcomes favourable)/(total number of outcomes)

Therefore P(no red/green)=1-(8/21+6/21)

=1-(8+6)/21=1-14/21=(21×1-14)/21=(21-14)/21

=7/21=1/3 ans

Step-by-step explanation:

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