Respuesta :
The molarity of each ion is obtained from the number of moles and volume of solution
From the question, the mass of the solution is 1.00 Kg and the density of the sample is 1.025 g/cm³.
From this, we can calculate the volume of the solution as follows;
D = M/V
V = M/D = 1 × 10^3 g/1.025 g/cm³
V = 976 cm³ or 0.976 L
Recall that number of moles = mass/molar mass
For NaCl = 26.5 g/58.5 g/mol = 0.45 moles
For MgCl₂ = 2.40 g/95 g/mol = 0.025 moles
For MgSO₄ = 3.35 g/120 g/mol = 0.028 moles
For CaCl₂ = 1.20 g/111 g/mol = 0.011 moles
For KCl = 1.05 g/75 g/mol = 0.014 moles
For NaHCO₃ = 0.315 g/84 g/mol = 0.0038 moles
For NaBr = 0.098 g/103 g/mol = 0.00095 moles
Molarity of each solution = number of moles/volume
For NaCl = 0.45 moles/0.976 L = 0.46 M
For MgCl₂ = 0.025 moles/0.976 L = 0.026 M
For MgSO₄ = 0.028 moles/0.976 L = 0.029 M
For CaCl₂ = 0.011 moles/0.976 L = 0.011 M
For KCl = 0.014 moles/0.976 L = 0.014 M
For NaHCO₃ = 0.0038 moles/0.976 L =0.0039 M
For NaBr = 0.00095 moles/0.976 L = 0.00097 M
The molarity of Na^+ and Cl^- = 0.46 M each
The molarity of Mg^2+ = 0.013 M while the concentration of Cl^- = 0.026 M
The molarity of both Mg^2+ and SO4^2- ions are 0.029 M each
The molarity of Ca^+ is 0.0055 M while the concentration of Cl^- is 0.011 M
The molarity K^+ and Cl^- are both 0.014 M
The molarity of both Na^+ and HCO3^- are both 0.0039 M
The molarity of both Na^+ and Br^- are both 0.00097 M
The total molarity of Na^+ = 0.46 M + 0.0039 M + 0.00097 M = 0.465 M
The total molarity of Ca^+ = 0.0055 M
The total molarity of Mg = 0.013 M + 0.029 M = 0.042 M
The total molarity of K^+ = 0.014 M
The total molarity of Cl^- = 0.46 M + 0.026 M + 0.011 M + 0.014 M = 0.511 M
The total molarity of SO4^- = 0.029 M
The total molarity of HCO3^- = 0.0039 M
The total molarity of Br^- = 0.00097 M
The total molarity of alkali metal ions = 0.465 M + 0.014 M = 0.479 M
The total molarity of alkaline earth metal ions = 0.0055 M + 0.042 M = 0.0475 M
The total molarity of anions = 0.511 M + 0.029 M + 0.0039 M + 0.00097 M = 0.545 M
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