The final velocity of the tailback after traveling an additional 10 m is 5.48 m/s.
The given parameters;
The final velocity of the tailback is calculated by applying the third kinematic equation;
v² = u² + 2as
where;
v is the final velocity of the tailback
v² = (5)² + 2(0.25 x 10)
v² = 25 + 5
v² = 30
v = √30
v = 5.48 m/s
Thus, the final velocity of the tailback after traveling an additional 10 m is 5.48 m/s.
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