Answer:
Answer: The third equation
Step-by-step explanation:
From the general equation of a line:
[tex] \hookrightarrow \: { \boxed{ \tt{y = mx + b}}}[/tex]
• m is the slope
[tex]{ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1}} }} \\ \\ m = { \tt{ \frac{ - 1- ( - 2)}{4 - 0} = \frac{1}{4} }}[/tex]
• b is the y-intercept:
[tex]{ \tt{y = mx + b}}[/tex]
consider point (0, -2):
[tex]{ \tt{ - 2 = (0 \times \frac{1}{4} ) + b }} \\ \\ { \tt{b = - 2}}[/tex]
• Therefore, equation is;
[tex] \dashrightarrow \: { \boxed{ \tt{y = \frac{1}{4}x - 2 }}}[/tex]
