The position of the object with respect to the ground is 8.48 m
The given parameters;
- height of the building, h = 24 m
- time of motion, t = 1.78 s
The distance traveled by the object will be calculated by applying second kinematic equation.
The distance traveled by the object after 1.78 s is calculated as;
[tex]y = v_0t + \frac{1}{2} gt^2\\\\[/tex]
y = 0 + (0.5 x 9.8 x 1.78²)
y = 15.52 m
The position of the object with respect to the ground is calculated as;
h = 24 m - 15.52 m
h = 8.48 m
Thus, the position of the object with respect to the ground is 8.48 m
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