Respuesta :

D will be 48

ATQ

[tex]\\ \bull\tt\dashrightarrow 48+48+(90-x)=180[/tex]

[tex]\\ \bull\tt\dashrightarrow 96+90-x=180[/tex]

[tex]\\ \bull\tt\dashrightarrow 186-x=180[/tex]

[tex]\\ \bull\tt\dashrightarrow 186-180=x[/tex]

[tex]\\ \bull\tt\dashrightarrow x=6[/tex]

Answer:

In the figure, m‹A = 90°

• Therefore:

[tex]{ \tt{x + 48 \degree = 90 \degree}} \\ \dashrightarrow \: { \sf \{angles \: of \: isosceles \: triangle \}} \\ \\ { \tt{x = 90 \degree - 48 \degree}} \\ \\ \dashrightarrow{ \boxed{ \boxed{ \tt{ \: \: x = 42 \degree \: \: }}}}[/tex]

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