When the constant force applied to an object, causing an acceleration of 9.0 m/s², is doubled, the final acceleration is also doubled.
The acceleration is related to the force by Newton's second law:
[tex] F = ma [/tex]
Where:
F. is the force applied
m: is the object's mass
a: is the acceleration
For the first case, when a constant force is applied and the acceleration is 9.0 m/s², we have:
[tex] F_{1} = ma_{1} = 9m [/tex] (1)
Now, when the force is doubled:
[tex] F_{2} = ma_{2} [/tex]
[tex] 2F_{1} = ma_{2} [/tex]
[tex] a_{2} = \frac{2F_{1}}{m} = \frac{2*9m}{m} = 18 m/s^{2} [/tex]
Therefore, when the force doubles, the acceleration also doubles.
To find more about Newton's second law, go here: https://brainly.com/question/23845187?referrer=searchResults
I hope it helps you!
