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pratap puri rowed 26 miles down a river in 2 hours, but the return trip took him 6 1/2 hours. find the rate pratap can row in still water and find the rate of the current. Let x= rate Pratap can row in still water and y=rate of the current

Respuesta :

Cricetus

The rate of current will be "4.5 mph" and the rate Pratap can row in still water will be "8.5 mph".

Given:

  • Distance "26 miles" in time "2 hours".

Let,

  • Speed of water = y
  • Pratap speed when rowing in still water = x

As we know,

→ [tex]Speed = \frac{Distance}{Time}[/tex]

then,

→ [tex]x+y = \frac{26}{2}[/tex]

→ [tex]x+y = 13[/tex]

→       [tex]x = 13-y[/tex]

In return trip took him time "6.5 hours",

→ [tex]x -y =\frac{26}{6.5}[/tex]

→ [tex]x -y = 4[/tex]

By substituting the value of "x", we get

→ [tex]13-y-y=4[/tex]

      [tex]13-2y=4[/tex]

              [tex]2y= 13-4[/tex]

                [tex]y = \frac{9}{2}[/tex]

                   [tex]= 4.5 \ mph[/tex] (Rate of the current)

By substituting the value of "y", we get

→ [tex]x = 13-a[/tex]

   [tex]x = 13-4.5[/tex]

      [tex]= 8.5 \ mph[/tex] (Pratap can row in still water)

Thus the above answer is correct.

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