Respuesta :

[tex]\\ \bull\tt\dashrightarrow BC=CE[/tex]

[tex]\\ \bull\tt\dashrightarrow 3x+3y=7x+5y[/tex]

[tex]\\ \bull\tt\dashrightarrow 7x-3x=3y-5y[/tex]

[tex]\\ \bull\tt\dashrightarrow 4x=-2y[/tex]

[tex]\\ \bull\tt\dashrightarrow 2x=-y[/tex]

[tex]\\ \bull\tt\dashrightarrow \dfrac{x}{y}=\dfrac{-1}{2}[/tex]

Now

[tex]\\ \bull\tt\dashrightarrow BE=BC+CE+CD[/tex]

[tex]\\ \bull\tt\dashrightarrow BE=3x+3y+7x+5y+5x-2y+6[/tex]

[tex]\\ \bull\tt\dashrightarrow BE=15x+6y+6[/tex]

Answer:

• BC = CD

[tex](3x + 3y) = (5x - 2y + 6) \\ 5x - 3x = - 2y - 3y + 6 \\ 2x = - 5y + 6 \\ \\ \dashrightarrow \: { \tt{x = \frac{ - 5y + 6}{2} }}[/tex]

• find BE:

[tex] \dashrightarrow \: { \tt{BE = (3x + 3y) + (7x + 5y)}} \\ \\{ \tt{BE = 10x + 8y}}[/tex]

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