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Find the perimeter of the triangle with the vertices at (0,2),(-1,2), and (-6,-4).

Respuesta :

caylus

Answer:

Step-by-step explanation:

A=(0,2), B=(-1,2), C=(-6,4)

AB²=(-1-0)²+(2-2)²=1 ==> AB=1

BC²=(-6+1)²+(4-2)²=25+4=29 ==> BC=√29

AC²=(-6-0)²+(4-2)²=36+4=40 ==> AC=√40

AB+BC+CA=1+√29+2√10≈12,7097

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