Respuesta :

[tex]\\ \ast\sf\hookrightarrow AC=2AB[/tex]

[tex]\\ \ast\sf\hookrightarrow 3x-1=2(x+6)[/tex]

[tex]\\ \ast\sf\hookrightarrow 3x-1=2x+12[/tex]

[tex]\\ \ast\sf\hookrightarrow 3x-2x=12+1[/tex]

[tex]\\ \ast\sf\hookrightarrow x=13[/tex]

AikoMikan

Hey there!

We are given that, AB is the midpoint of AC, so it indicates that :-

  1. AC = AB + BC --- 1
  2. AB = BC --- 2
  3. AC = 2AB (AB = BC --- 2) --- 3

So, the value of BC = x + 6 (from --- 2)

Now, let's solve for 'x' using --- 3

AC = 2AB --- 3

3x - 1 = 2(x + 6)

3x - 1 = 2x + 12

3x - 2x = 12 + 1

x = 13.

Refer to the picture for better understanding.

Hope it helps ya!

Ver imagen AikoMikan