Respuesta :

[tex]\\ \ast\sf\hookrightarrow AB=2AC[/tex]

[tex]\\ \ast\sf\hookrightarrow 3x+2=2(2x-1)[/tex]

[tex]\\ \ast\sf\hookrightarrow 3x+2=4x-2[/tex]

[tex]\\ \ast\sf\hookrightarrow 4x-3x=2+2[/tex]

[tex]\\ \ast\sf\hookrightarrow x=4[/tex]

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[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

DE bisects AB at C. If AC = 2x - 1 and AB = 3x + 2, find x.

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

We know that,

  • DE bisects AB at C.
  • So, AC + CB = AB (C becomes the mid-point of AB).
  • We can also see that, AB = BC, so 2AC = AB

Now, find the value of x.

For this, we need to use the equation ⇨ 2AC = AB.

__________

2AC = AB

2 (2x - 1) = 3x + 2

4x - 2 = 3x + 2

4x - 3x = 2 + 2

[tex]\boxed{\underline{\bf \: x = 4}}[/tex]

  • The value of x is 4.

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