The combustion reaction for Fe₃O₄ in an oxygen molecule O₂ yields Fe₂O₃.
The number of moles of Fe₃O₄ required to prepare 0.472 moles of Fe₂O₃ is:
0.315 moles
The reaction equation is:
[tex]\mathbf{4Fe_3O_4+O_2 \to 6Fe_2O_3}[/tex]
From the above reaction;
4 moles of Fe₃O₄ react with oxygen to produce 6 moles Fe₂O₃.
i.e.
Fe₃O₄ : Fe₂O₃ = 4 : 6
Fe₃O₄ : Fe₂O₃ = 2 : 3
[tex]\mathbf{ = \dfrac{2}{3}\times 0.472}[/tex]
= 0.315 moles
Therefore, we can conclude that 0.472 moles of Fe₂O₃ are prepared from 0.315 moles of Fe₃O₄.
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